Question

Find the general solution to these differential equations
dy/dx=y-3

Answer 1

@agent0smith

Answer 2

the answer was \[y=Ce^x + 3\]

Answer 3

\[\frac{ dy}{ dx}=y-3 = 1(y-3)\]
\[\frac{ dy }{ y-3 } = 1 dx\]
Now integrate both sides, then you'll have to take the power of e on both sides.

Answer 4

\[\frac{ 1 }{ y-3 }=x+c\]

Answer 5

did i integrate it right?

Answer 6

on the left hand side?

Answer 7

You might want to try a substitution on the right... let u = x-3, then the integral of 1/u is ln u

Answer 8

wait nvm i got it lol

Answer 9

can you help me with another one please? <3