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OpenStudy (anonymous):
3x - 4y = 7
3x + 2y = -5
When the second equation is subtracted from the first, the resulting equation is _____.
@salehgeek
13 years ago
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OpenStudy (anonymous):
\(3x-4y=\) \(7\)
\(-(3x+3y=-5)\)
----------------
13 years ago
OpenStudy (anonymous):
its 2y not 3y
13 years ago
OpenStudy (anonymous):
Sorry:
\(3x-4y=\) \(7\)
\(-(3x+2y=-5)\)
------------------
13 years ago
OpenStudy (anonymous):
Solving this will give you \(-6y=...\)
13 years ago
OpenStudy (anonymous):
-6y= -12
-6y= 12
13 years ago
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OpenStudy (anonymous):
Which one did you get?
13 years ago
OpenStudy (anonymous):
-6y= -12
13 years ago
OpenStudy (anonymous):
It should be \(6y=12\)
Can you show how you got your answer?
13 years ago
OpenStudy (anonymous):
sorry \(-6=12\)
13 years ago
OpenStudy (anonymous):
3x + 5y = 78
2x - y = 0
The point of intersection of the lines has an x-coordinate of ___.
13 years ago
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OpenStudy (anonymous):
sorry \(-6y=12\)
13 years ago
OpenStudy (anonymous):
\(3x-4y=7\)
\(-3x-2y=5\)
------------------
\(0-6y=12\)
13 years ago
OpenStudy (anonymous):
x + 5y = -2
2x + y = 5
The point of intersection of the lines has a y-coordinate of ___.
13 years ago
OpenStudy (anonymous):
We rewrite the first equation in terms of x
\[x=-2-5y\]
Then, we plug the value of x in terms of y into the second formula:
\[2(-2-5y)+y=5\]
Upon solving for y we have:
\[y=-1\]
13 years ago
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