Solve: –2(x – 3) ≥ 5 – (x + 3)
My answer is –2(x – 3) ≥ 5 – (x + 3) -2x – 6 > 5x + 15 - 5x - 5x -7 – 6 > + 15 + 6 + 6 -7 > 21 x < -3
on your first step, when you distributed the -2 it would make the 6 positive, not negative.
and on the other side, there is a subtraction sign between so you dont distribute
so what do I do to the other side?
it would look like this
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–2(x – 3) ≥ 5 – (x + 3) -2x+6>=5-x-3 -2x+6 >=2 - x how will I subtract 6 from x?
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now I divide 4 by 2?
i would add the x so it would be -x-4>=0 then just add 4 -x>=4 and divide by a negative
–2(x – 3) ≥ 5 – (x + 3) -2x+6>=5-x-3 -2x+6 >=2 - x -2x+6>=2-x -2x-4>=-x -x-4>=0 -x>=4
you got it!
and to check if its right I replace x with 4? –2(4 – 3) ≥ 5 – (4 + 3) -8 - 6 > 5 - 7 -2 -2
well, you would have to make sure you divide the -x>=4 by a negative because x needs to be alone so it would be x=<-4, so you would plug back in -4 and/pr a number less than to see if it works!
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