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reduce (t^2y^3)/(ac)
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\[\frac{ t^2y^3 }{ ac }\]
Are there any common factors?
no
Then it is already in simple form.
that is what i thought,,, to write it without a denominato it would be: t^2y^3(1/(a1/c) correct??
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@MusicTeacher are we supposed to be able to read that
To write it so the the only denominator is 1 (which is typically not written) you would have to bring the denominator factors to the numerator by changing the sign of their exponents.
\[t^2y^3 (a^-1(c^-2)\]
c^-1,,,,
\[t^2y^3a ^{-1}c ^{-1}\]
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yay! i got it !!! tytyty
wy
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