Write the equation of the line that is perpendicular to the line y =3/2 x + 4 and passes through the point (−6, 3).

y = 3/2x − 1

y = 3/2x + 3

y = −2/3x − 1

y = −2/3x + 3

Question

Write the equation of the line that is perpendicular to the line y =3/2 x + 4 and passes through the point (−6, 3).

 y = 3/2x − 1

 y = 3/2x + 3

 y = −2/3x − 1

 y = −2/3x + 3

anonymous · Answer

try using the form 
(y-y1)=m(x-x1)
you put the points given to you(-6,3) in the spots of y1 and x1,
and since it is perpendicular, you know the slope is...?

anonymous · Answer

B?

anonymous · Answer

when you have a perpendicular line, the slop of that line is the opposite, so in this case the original line is 3/2, the perpendicular would be -2/3

anonymous · Answer

So D?

anonymous · Answer

yuppp!

anonymous · Answer

Nice! Thanks! Love you name btw

anonymous · Answer

why thank you :) that tis my real name...a lot of people on here think it isnt.

anonymous · Answer

Nah why would I think it's not lol, hope os a beautiful name for a girl

anonymous · Answer

haha, idk they call me nicole a lot its funny. and why thank you :) i like it!

anonymous · Answer

no problem:)