4x+y=-1 4x+3y=-8
\[4x+y=-1 \rightarrow 4x =-1 - y\]\[4x+3y=-8\] \[(-1 - y)+3y=-8 \rightarrow 2y = -7 \rightarrow y = -7/2\]\[4x=−1−(-7/2) \rightarrow 4x = 5/2 \rightarrow x = 5/8\]
Correction: \[4x=−1−(−7/2) =5/2 \rightarrow x=5/8\]
still need help ?
yeah
subtract the 2 equations, what u get ?
Do you need the steps in elimination or substitution?
\[4x+y=-1[1]\] \[4x+3y=-8[2]\] \[[2]-[1]\] \[(4x+3y)-(4x+y)=(-8)-(-1)\]
-2y=7 y=-3.5
thats correct, what about 'x' ?
8x=-9 x=-1.125
4x-3.5=-1 4x = -1+3.5 4x = 2.5 x= 2.5/4 or 5/8 how you got 8x=-9 ?
wait, but y is supposed to be add...you know where it says 4x-3.5 , it's supposed to be 4x+3.5
right?
but y itself is negative, 4x + (-3.5) = 4x-3.5
ok here is my solution for y... 4x+y=-1 4x+3y=-8 2y= 7 y=3.5 how did you get -3.5?
3y-y = -8 -(-1) = -8+1 = -7 so, 2y =-7 y= -7/2 = -3.5
-8-(-1) is actually -7
ohhhhh, ok thank you it's clear now
Join our real-time social learning platform and learn together with your friends!