The 2000 census "long form" asked the total 1999 income of the householder, the person in whose name the dwelling unit was owned or rented. This census form was sent to a random sample of 17% of the nation's households. Suppose that the households that returned the long form are an SRS of the population of all households in each district. In Middletown, a city of 40,000 persons, 2621 householders reported their income. The mean of the responses was x = $33,453, and the standard deviation was s = $8721. The sample standard deviation for so large a sample will be very close to the population sta

Question

anonymous · Answer

standard deviation s. Use these facts to give an approximate 99% confidence interval for the 1999 mean income of Middletown householders who reported income.

anonymous · Answer

@amistre64 @.Sam.

mertsj · Answer

Well I don't really know stats but how many standard deviations each way does it take to include 99%?

anonymous · Answer

Yeah, I need help with this question as well; I have no idea on how to do it. Hopefully you'll get an explanation/answer to this question soon, haha.