A line passes through the points (-8, 7) and (x2, y2), and has a slope of -1/10. If point (x2, y2) is located in quadrant I, find x2.
ok, so we know a couple of things, we know the slope, we know that the point lies in QI, so we should have all we need to answer the question.
ok
is what i have told you made sense so far?
yes
Our slope formula is \[m=\frac{ y _{2}-y _{1} }{x _{2}-x _{1} }\]
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OOPs, didn't mean to bust into your explanation @Hope_nicole
its okay
you can help if you want to
Let's substitute the values we know into the slope formula....
We know m, we know x_1 and y_1
i already did @Hope_nicole help me do that already we got y=-1/10+6.2
well, I was thinking more like this: \[y _{2}-7=-1\] and \[ x _{2}-8=10\]
Now just solve for each of those separately and you have your answer.
6 and 18
There you go, so your x value is what you were looking for.
so the x is 18
Most importantly, the values fit the description that the point is in Q1 because (18,6) lies in Q1.
thanks
YW!
did he help you? sorry my dogs decided to run throw a mud puddle!
is he right
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