Find the inverse Laplace Transform of

(s+4)/(s^2+8s+17)

Question

Find the inverse Laplace Transform of 

(s+4)/(s^2+8s+17)

experimentx · Answer

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anonymous · Answer

the example in the book is pretty tough to make sense of, I am not sure what I am supposed to do next? 

Why did you have to re-write the denominator?

experimentx · Answer

what factor shifts the value of s?

anonymous · Answer

ohhh wait, you just try to re-write each transform and just follow a table? 

i see there is a table that says e^alphax(cos betax) = (s-alpha)/(s-alpha)^2 + beta^2

so alpha is just -4 and beta is 1, so the

f(x) = e^-4x cos x ??? this correct?

experimentx · Answer

yes ... e^(-ax) shifts the value of the transform ... while is is in the form of cos(bx) .. not that difficult .. is it?

anonymous · Answer

nope not at all, well I guess depending on what i need to deconstruct.... 

so i need a e^-4x sin x to go with that as well right?

experimentx · Answer

i almost forgot everything with laplace transform