Question

how amplitude is obtained?

Answer 1

This depends on context...

Answer 2

In general, find the distance between the get top and the very bottom and half that.

Answer 3

If you have a sin/cos function, then the amplitude will just be the coefficient in front of it.

Answer 4

yeah yeah. y=asin(bx)+d, but for the assignment it says to give an explanation and justification of how they were obtained. I know its max-min/2, but i dont know how to explain how that works?

Answer 5

The amplitude of y = sin(x) is 1

The amplitude of y = A*sin(x) is |A|

Answer 6

basically the "A" vertically stretches the graph of y = sin(x) by a factor of |A|, so that explains why the amplitude jumps from 1 to |A|

Answer 7

ah thank you! do you know much about apparent frequency?

Answer 8

not too familiar with apparent frequency, but I do know that frequency is

f = 1/T

where T = period

Answer 9

yeah i know that also, but we have a beat function with 2 frequencies. So it says that the apparent frequency is the is the number of beats over the interval of 2pi. To justify it, do you think its enough to say that the number of beats is the difference between the pair of frequencies?

Answer 10

hmm not too sure, sorry

Answer 11

thats alright, thanks heaps for your help!!

Answer 12

yw

Answer 13

ah wait, does it make a difference if it says the maximum amplitude?

Answer 14

what do you mean

Answer 15

whats the difference between the maximm amplitude and normal amplitude? my function is y=2cos(5/2x)cos(35/2x). The amplitude for the function is 2 because of the general equation y=acos(bx)+d, but the maximum amplitude is max-min/2. Because the minimum of the graph is not exactly -2 (its -1.806), the maximum amplitude is 1.905. What the difference, do you know?

Answer 16

I'm getting roughly 1.90128 as the largest distance from the midline to the furthest point out

Answer 17

so it looks like the maximum amplitude is 1.90128

Answer 18

yeah, which is roughly around what i got using Graphmatica. I am just very confused as to how i justify getting that, like how max-min/2 works everytime?

Answer 19

as for the difference, I think it's a case where you're measuring only a piece of the curve for the normal amplitude

but with the maximum amplitude, you're measuring the furthest distance possible (in a vertical direction)

Answer 20

max - min will give you the distance the max point is from the min

cut that in half and you'll get half that distance, which is the amplitude

Answer 21

yeah but why does that work everytime?

Answer 22

say you want to find the distance from 7 to 18

Answer 23

you would do

18 - 7 = 11

so 7 is 11 units from 18

Answer 24

so if you have 18 as the max y value and 7 as the min y value, then half of this distance is 11/2 = 5.5, which is the amplitude