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(6a-10) is this still possible to factor?
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Take out a factor of 2 :)
2(3a-5) is the result.
i had a question it was 36a^-100a^2 i did a^2(36a^-100) and i got a^2(6a+10)(6a-10) so if i take out 2 it will be a^2(6a+10) 2(3a-5) ????????
a^2(36a-100) = 4a^2(9a-25)
sorry i wrote i wrong 36a^4 - 100a^2 i take out a^2(36a^2-100) and that equals a^2(6a+10)(6a-10) right ??
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Oh right yeah that is correct. Then you can take a factor of 2 from both of the parts inside the brackets to get a factor of 4 you take out. (a^2)2(3a+5)2(3a-5) = 4a^2(3a+5)(3a-5)
thank you so much!!
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