Question

For the following reaction, 6.12 grams of chlorine gas are mixed with excess iron. The reaction yields 8.25 grams of iron(III) chloride.


2 Fe (s) + 3 Cl2 (g) 2 FeCl3 (s)





(1) What is the theoretical yield of iron(III) chloride ?

grams



(2) What is the percent yield for this reaction ?

%




For the following reaction, 6.12 grams of chlorine gas are mixed with excess iron. The reaction yields 8.25 grams of iron(III) chloride.


2 Fe (s) + 3 Cl2 (g) 2 FeCl3 (s)





(1) What is the theoretical yield of iron(III) chloride ?

grams



(2) What is

Answer 1

For the following reaction, 6.12 grams of chlorine gas are mixed with excess iron. The reaction yields 8.25 grams of iron(III) chloride.


2 Fe (s) + 3 Cl2 (g) 2 FeCl3 (s)





(1) What is the theoretical yield of iron(III) chloride ?

grams



(2) What is the percent yield for this reaction ?

Answer 2

same steps as before
give it a shot

Answer 3

2 Fe (s) + 3 Cl2 (g)= 2 FeCl3 (s

Answer 4

express in mole fractions..

Answer 5

2 MOLES

Answer 6

I HAVE NEVER DONE THIS BEFOR

Answer 7

i HAVE DIFFICULT COMPREHENDING THIS STUFF

Answer 8

its ok..
thats why we go to school.

Answer 9

HOW DO WE START THIS

Answer 10

we are concerned only with Cl and FeCl3

Answer 11

so, how many moles of Cl react to give how many moles of FeCl3?

Answer 12

1 MOLE

Answer 13

no.. 3 moles of Cl2 react to give 2moles of FeCl3
(look at the equation)

Answer 14

right?

Answer 15

OKAY

Answer 16

so, 3*(gmw of Cl2) -> 2*(gmw of FeCl3)

Answer 17

so, amount of FeCl3 = 3*6.12/2 theoretically

Answer 18

=9.18g

Answer 19

hurry up