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Why is the exterior angle of a triangle equal to the sum of the two remote interior angles?
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I can't see the whole drawing,,, @agostino
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In words, consider a triangle with angles a, b, c. Say we extend a side of the triangle such that there is another angle d which satisfies d=180-c, i.e. an exterior angle of the triangle. We have a+b+c=180 and by c+d=180, we have a+b=d.
\[A+B+C=180\]PROPERTY OF TRIANGLE SUM\[D=180-C\]SUPPLEMENTARY ANGLES\[NOW C=180-D \]
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SUBSTITUTE IT INTO THE 1ST EQUATION
A+B+(180-D)=180 A+B+180-D=180 A+B=D
thanks guys!
HENCE PROVED!!
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