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what is the inverse of y = 3x² - 11x - 4
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switch all the x's and y's y = 3x² - 11x - 4 becomes x = 3y² - 11y - 4 now solve for y again
what would you do after \[x+4=3y ^{2}+11y\]
I meant to say x+4=3y^2-11y
from: x = 3y² - 11y - 4 x+4 = 3y² - 11y - 4 x+4 = y ( 3y - 11) \[y=\frac{x+4}{3y-11}\]
the inverse of y=mx+c = y ^ -1 (that is inverse, swaping x n y) therefore it would be x=my+c, solve for x therefore 1. x - c = my 2. (x - c) / m = y, hope this helps
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thanks
The inverse of a squared expression is going to be an expression involving a square root.
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