Question

differentiate the function H(z)= ln [(a^2-z^2)^1/2]/[(a^2+z^2)^1/2]

Answer 1

This is your function:

\(H(z)= \dfrac{\ln (a^2-z^2)^{1/2}}{(a^2+z^2)^{1/2}}\).

Is that right?

Answer 2

yes

Answer 3

Start with quotient rule and then follow up with chain rule.