Question

Please help!?!????


Find an equation in standard form for the hyperbola with vertices at (0, ±6) and asymptotes at y = ± 3/4x?

Answer 1

@Directrix

Answer 2

\[
\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1
\]

Answer 3

h, k -> from vertices
a,b from slopes of asymptotes

Answer 4

(x-6)^2/9 + (y-k)/16= 1

Answer 5

Did I do the denominators right? Please help me with the rest! I just don't get it

Answer 6

@electrokid

Answer 7

@Hero