Question

what is the minimum value of the function f(x)=2x^2-4x+1?

Answer 1

f(x)=2x^2-4x+1

differentiate it.

Answer 2

After then what to do will be said by @satellite73 SIR

Answer 3

or look for the second coordinate of the vertex
first coordinate is always \(-\frac{b}{2a}\)

Answer 4

@satellite can you Help in my preparation in My Exam ?

Answer 5

WHAT DOES MINIMUM VALUE MEAN?

Answer 6

What does minimum value mean?

Answer 7

it means the smallest value that \(y\) can be

Answer 8

so what would the minumum value in this eqution be

Answer 9

\[f(x)=2x^2-4x+1 \]
\[f(x)=ax^2+bx+c\] in this case \(a=2,b=-4\)
so \(\frac{-b}{2a}=-\frac{-4}{2\times 2}=1\) that is the first coordinate of the vertex
second is \(f(1)\)

Answer 10

hihihi hope this helps