calcII y=6-x, y=0, x=4, x=2 around the y-axis ans 104pi/3 drawing below
|dw:1363576409366:dw|
here's what i have so far, int2,4(6-x)^2pidx
what are you trying to find here?
Looks like volume of solid after revolving about y-axis?
yes, pretty much
If that's the case, your integral doesn't look right. The way you've set it up would be the volume of the solid if you were to revolve it about the x-axis.
ya, that's probably one thing i got wrong.
volume of outer cylinder-type - volume of inner cylinder-type
V1 - V2 for each one use disc or shell method. they are linear boundaries so, should be nice enough
Yep, but with the disk method you'll have to use two integrals. I'd stick with shells for this one.
Using shell method,\[V=2\pi\int_2^4x\cdot(6-x)\;dx\]|dw:1363577496833:dw|
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