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Mathematics 16 Online
OpenStudy (anonymous):

calcII y=6-x, y=0, x=4, x=2 around the y-axis ans 104pi/3 drawing below

OpenStudy (anonymous):

|dw:1363576409366:dw|

OpenStudy (anonymous):

here's what i have so far, int2,4(6-x)^2pidx

OpenStudy (anonymous):

what are you trying to find here?

OpenStudy (anonymous):

Looks like volume of solid after revolving about y-axis?

OpenStudy (anonymous):

yes, pretty much

OpenStudy (anonymous):

If that's the case, your integral doesn't look right. The way you've set it up would be the volume of the solid if you were to revolve it about the x-axis.

OpenStudy (anonymous):

ya, that's probably one thing i got wrong.

OpenStudy (anonymous):

volume of outer cylinder-type - volume of inner cylinder-type

OpenStudy (anonymous):

V1 - V2 for each one use disc or shell method. they are linear boundaries so, should be nice enough

OpenStudy (anonymous):

Yep, but with the disk method you'll have to use two integrals. I'd stick with shells for this one.

OpenStudy (anonymous):

Using shell method,\[V=2\pi\int_2^4x\cdot(6-x)\;dx\]|dw:1363577496833:dw|

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