Question

Find the derivative of
a(x)=x^2*2^x

Answer 1

Use the product rule: d/dx(x^2)*2^x+x^2*d/dx(2^x)

Answer 2

ok so would the answer be 2x*ln2*2^x

Answer 3

No. Remember the addition part of the product rule. Seems you clumped everything together.
it's f'(x)g(x)+f(x)g'(x)

Answer 4

oh right so then 2x*2^x+x^2*ln2

Answer 5

\[\huge product rule\]

Answer 6

2x+ln2*2^x

Answer 7

\[2x*2^x+\ln2*2^x*x^2\]

Answer 8

oh I was messing it up cause I was writing it wrong I got it know my answer matches you now

Answer 9

=\[x*2^{x+1}+\ln(2)*x^2*2^x\]

Answer 10

can'tI leave it the other way

Answer 11

this should be the answer

Answer 12

\[\huge (\ln(2)*x^2+2x)*2^x\]

Answer 13

ok well all my multiple choice answer don'tgive that for a choice all that is similar to it would be 2x*2^x+x^2*ln2*2^x

Answer 14

and this one??

Answer 15

what do you mean and theis one