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Physics 17 Online
OpenStudy (dls):

"When the body topples,frictional force is less than umg" umg is the max value of friction I guess,so coeffecient of friction

OpenStudy (dls):

@experimentX @Vincent-Lyon.Fr @Mashy Someone please?

OpenStudy (anonymous):

how can you relate between Coefficient of friction and max value of friction!? they are two different physical quanties :P.. and i didn't get your doubt :-/

OpenStudy (dls):

"When the body topples,frictional force is less than umg"" explain this!

OpenStudy (anonymous):

i think what you are saying is when a body topples while negotiating a curve, the Max value of frictional force is less than CENTRIPETAL FORCE required

OpenStudy (dls):

no ? :/ lol

OpenStudy (anonymous):

thats the case when a body topples :P..

OpenStudy (dls):

And what happens when the body topples? The body moves,but yet frictional force<umg.This is very important point.Students need to visualize this scenario very clearly in their minds.When the body topples,frictional force is less than umg.Also it requires less efforts to move a body. If this is so..why doesn't a square body not topple so easily? The reason is very simple.The coefficient of friction needs to be higher than 0.5( i know why :O) for a square body.This does not happen in reality because u=0.5,the surface must be really very tough. I got the answer to the question but why does it have to be less than umg ? :/ just a bit confused.. hmm typed too much :P

OpenStudy (dls):

@RnR

OpenStudy (dls):

that is what is written in my book^^

OpenStudy (anonymous):

all i know is something very simple if the required centripetal force is less than the max static friction between the tyre and the road the body will topple.. as simple as that :-/ search some problem!

OpenStudy (anonymous):

more than*

OpenStudy (anonymous):

yahan centripetal kahan se aa gyi? :O

OpenStudy (dls):

exactly :P

OpenStudy (dls):

If the co-efficient of friction=0.2 what will happen to the square?Will it topple or translate? If the co-efficient of friction=0.6 what will happen to the square?Will it topple or translate? force for toppling for a square>0.5mg right :|

OpenStudy (dls):

a question,but i would love an answer to the theory ques!

OpenStudy (anonymous):

wait.. you are talking about TAKING A TURN right?

OpenStudy (dls):

here,maximum value of friction=0.2 which is less than 0.2mg O.o doesnt make any sense and NO WTH?

OpenStudy (dls):

just a square llying on table :|

OpenStudy (anonymous):

Arggg.. you mean SLIDING!???

OpenStudy (anonymous):

LOL. A box is lying on the ground. We are applying a force at the topmost edge from the right hand side.

OpenStudy (anonymous):

sliding/toppling.

OpenStudy (anonymous):

OHHHH!! :D :D :D :D !!!

OpenStudy (dls):

idk which centripetal force is he talking about :P

OpenStudy (dls):

lol..

OpenStudy (anonymous):

ok ok ok nvr mind.. i thought toppling when you take a turn!! :D

OpenStudy (dls):

:/

OpenStudy (anonymous):

ok now tell me .. what you mean a SQUARE?? you mean a CUBE right?? not a square lamina lying on the ground right?

OpenStudy (dls):

square :/

OpenStudy (dls):

square body

OpenStudy (anonymous):

squre body!?? :-/.. you mean a 2d lamina???

OpenStudy (dls):

HOW DOES IT MATTER ? :/ im telling the force for topling>0.5mg!!

OpenStudy (dls):

answer it now! dam

OpenStudy (anonymous):

just iamgine a square body.. |dw:1363620293705:dw|

OpenStudy (anonymous):

I'm out. solve kr dena. :P

OpenStudy (anonymous):

i can't understand square body!?? it is three dimensional body right?? like this?? |dw:1363620388440:dw|

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