Need an explanation please - integrals.
I am just wondering how 5^2x goes into 5^2x/2ln5 .. i know the formula, i'm just wondering where the 2 comes from ... is it because of the 5^2x, so since it's 2x i have to take 1/2 outside the integral sign? also... i am wondering how to get the integral of 5^2x/2ln5x. i know what the answer is, i just don't know how to get it.
\[ {d\over dx}(a^x)=a^x\ln(a)\\ \implies \int a^xdx=\frac{a^x}{\ln a} \] now, set \[ u=2x\implies dx=\frac{du}{2}\\ \int5^{2x}dx=\int5^u\frac{du}{2}=\frac{5^u}{2\ln5}+C\\ =\frac{5^{2x}}{2\ln5}+C \]
okay now i'm just wondering how i would integrate that answer. (im doing integration by parts)
that is the answer. no need to use integration by parts.
5^(2x) = 25^x
ok
just old substitution with this trick ... |dw:1363623298064:dw|
can you please explain a little more?
|dw:1363623465329:dw|
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