I need to find sin(4a) if tga=3/4 what I do: \[\sin(4a)=2\sin(2a)\cos(2a)\] \[tg=\frac{ sina }{ cosa }\]
can you help me @arifadli8
sorry i cant help u
hint... does it look like a 3-4-5 triangle to anyone?
|dw:1363626168997:dw| if not, follow hartnn's steps
shouldnt be included*
I have never learnt about sec at school, so I think it shouldnt be included in finding the answer. Any other tips?
not needed.. tangent is opp side / adj side |dw:1363626280339:dw|
|dw:1363626280339:dw| no need. you know that tangent = opp side / adj side
yes
and find the third side, the hypotensuse.. (Pythagorean them) then, sin = opp side / hypotenuse.
so, you'd get opp side = 3 adj side = 3 hyp = 5
now, keep splitting sin(4A) till you get it in terms of sin(A) and cos(A)
but, actually, it is not true. Where from you find it is 3 and 4? : ) it also can be 12 and 9
as long as you maintain the (3/4) ratio, you are good :)
keeping things simple will always help
well, wont it change sin value?
and also, I have forrgoten to say pi<a<3/2pi
nope.. the ratio you'd get is still the same.. when you scale the ratio, only the "size" of triangle i.e., the sides change but the angles and ratios do not The golden rule of trigonometry
aha... now... things are a bit differet
well, I am still not sure if it is a rational way to do it. Because we can't say what we don't have.
|dw:1363626740966:dw|
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