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How do you find the vertex of y=x^2+6x+10 ?
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take derivative of y and let it =0. solve for x. and then, replace that x into original function to get y. those x and y are coordinate of the vertex of function
the x-coordinate for the vertex of any parabola is -b\(2a)
-b/(2a)
Would the answer be (-3,1) ?
if you did get \(\large f(-\frac{b}{2a})=1 \), .....
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I took that formula and got -3 for x. Then I plug -3 into the original equation to get y and got 1.
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