A ball is thrown vertically upward from the top of a 96 ft tower, with an initial velocity of 16 ft/sec. Its position function is s(t) = -16t2 + 16t + 96. What is its velocity in ft/sec when it hits the ground? (AWARD AND FAN)

Question

tkhunny · Answer

The position function $s(t) = -16t^{2} + 16t + 96$
Leads to the velocity function: $v(t) = -32t + 16$

Tell me first that you know where that $v(t)$ came from.
Tell me second the values of t for which s(t) = 0.
Tell me third which one is pertinent and which must be discarded.

One more thing after that.

anonymous · Answer

i don't know what any of those are ?