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Mathematics 9 Online
OpenStudy (anonymous):

Please help!

OpenStudy (anonymous):

what with

OpenStudy (anonymous):

\[1/4x^{2}+12=0\]

OpenStudy (anonymous):

figure out what number fits for x. start with lower numbers and go higher. I am not the best at these so i can not do it for you. Sorry.

OpenStudy (anonymous):

@ZeHanz

OpenStudy (zehanz):

Multiply with 4 on both sides: \(x^2+48=0\) This means \(x^2=-48\). There are no real numbers of which the square is negative, so there are no (real) solutions...

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