Question

Please help!

Answer 1

what with

Answer 2

\[1/4x^{2}+12=0\]

Answer 3

figure out what number fits for x. start with lower numbers and go higher. I am not the best at these so i can not do it for you. Sorry.

Answer 4

@ZeHanz

Answer 5

Multiply with 4 on both sides: \(x^2+48=0\)
This means \(x^2=-48\). There are no real numbers of which the square is negative, so there are no (real) solutions...