what is c that makes this a perfect square? x^2+5x+c?
what to you get if you expand ( y + 2.5)^2 ?
\[(a+b)^2 = a^2+2ab+b^2\]
consider the perfect square of: (x+b)(x+b) = x^2 +2bx + b^2, and compare that to the given equation
if 2b = 5 and c = b^2 id solve for b, and square it
that doesnt make sense
then you need to go back a few chapters and relearn some stuff ....
walk me through it?
had to get to class :) there are general trinomials: ax^2 + bx + c but what makes a trinomial a perfect square is when it can be produced from expanding a binomial squared. (x+b) is a binomial, 2 terms; when we square this ... when we multiply it by itself .... we produce a perfect square trinomial. (x+b)^2 = (x+b)(x+b) = x^2 + 2bx + b^2. All perfect square trinomials take this form
so we only need to compare your specific problem with the general setup and see what needs to be adjusted. x^2 + 2bx + b^2 x^2 + 5 x + c notice by comparing the forms, that the value of c will have to equal b^2 ... whatever "b" may be. we see that 2b compares to 5, this gives us an equation to solve: 2b=5 when we know what b has to be, then we know what b^2 has to be, and then since b^2 = c, we will know what c has to be .
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