Question

help. please.

Answer 1

first find x. solve for x in the equation:

(6x + 5) + (5x + 3) + (8x + 1) = 180

then to find m<CQD, plug the value for x into (8x + 1)

Answer 2

@dpaInc could you set up the equation for me for this problem pleasee.

Answer 3

there are several ways u can do this given LG is a diameter.
but the easier one would be to use the two angles on the left:

4x + 106.2 = 180

Answer 4

so x = 18.45?

Answer 5

what about this one its confusing ? @dpaInc

Answer 6

here
arc = 90*
so the angle from circumference is half of it
that's 45

Answer 7

option D is right

Answer 8

@aajugdar so is this one 40?

Answer 9

yes

Answer 10

what about this one what the formula to solve it?

Answer 11

2(6x+10)=160

Answer 12

that's 6x+10 =80
6x=70
x=11.6

Answer 13

alright thank you! what about this one its confusing for me too.. Im not sure what angle they want?

Answer 14

@aajugdar

Answer 15

i think you will have to proportionate this 1
give me some time

Answer 16

okay..

Answer 17

ok got it

Answer 18

arc AD and AC are 86 and 104 right
so sum of their angles = 84+104 =190
now
a circle is of 360
so 360-190 =170 is sum of other two angles
and angle AEC = 170/2 = 85

Answer 19

wait
that's not in option :D

Answer 20

hold on

Answer 21

no
you have to calculate AED
oh god
just divide 190/2 =95

Answer 22

how did you get that?

Answer 23

the opposite angles are same
so you just half it of the sum of arcs
that's (86+104)/2 = 95