In youngs double slit experiment slits are seperated by a distance d and screen is at a distance Dd. From a slit plane if a light source of wavelength lambda (

Question

In youngs double slit experiment slits are seperated by a distance d and screen is at a distance D>>d. From a slit plane if a light source of wavelength lambda (<

anonymous · Answer

@Mashy

anonymous · Answer

@experimentX

anonymous · Answer

Intensity.. argg.. i dunno what happens to intensity in double slit.. :P

anonymous · Answer

nvm. i might get it. 2 mins.

anonymous · Answer

I got 3. I dont know if its right though.

anonymous · Answer

Its good. Thank you.

experimentx · Answer

there should be a good relation between them, what is the relation between fringe width and d, D and lambda

anonymous · Answer

Well what i did is I know, I(resultant)=Imax cos^2(theta/2) where theta is path difference
and according to the question I(res)=Imax/4
Now phase diff=path diff *2pi/lambda
and path difference=Dy/d where y is position of the fringe.
We have to find y.

experimentx · Answer

Fringe width (x) = λD/d

anonymous · Answer

I dont fringe width will be needed here.

anonymous · Answer

dont think*

experimentx · Answer

looks like I am also not getting what you are trying to say ... are you done with it. I am quite busy right now I can't focus.

anonymous · Answer

No problem. I was done with it already.

experimentx · Answer

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