Question

-7x^2 + 6x + 3 = 0

Answer 1

Use \[x = \frac{ (-b \pm \sqrt{b ^{2}-4ac}) }{ 2a }\]

Answer 2

where a = -7, b = 6, c = 3

Answer 3

solve -7x^2 + 6x + 3 = 0 Whats the anwser
a.one solution
b.two solutions
c.no solutions
d.infinitely many solutions

Answer 4

In this case, since the \[\pm \sqrt{b ^{2}-4ac}\] is positive, there are two different solutions

Answer 5

what about -8x^2 - 8x - 2 = 0 ?

Answer 6

Use the same formula but with a = -8, b = -8 and c = -2, if the "\[b ^{2}-4ac\] is greater than zero, there are two solutions, if it is equal to zero there is only one solution, and if it's less than zero there are no (real) solutions