Solve the system by substitution.
Solving by substitution means that you take one of the equations and isolate for just one variable, then "substitute" it into the other. Following so far?
You can pick either equation to isolate with(doesn't matter). Your equations are: 2x + y = -11 and 3x -4y = 11 So I'll randomly choose the first one and isolate for y: 2x + y = -11 I'll subtract 2x from each side: 2x - 2x + y = -11 - 2x y = -11 - 2x
Now I'll substitute that into the other equation: ( y = -11 - 2x into 3x - 4y = 11 ) 3x - 4(-11 - 2x) = 11
If you distribute/multiply through: 3x - 4(-11 - 2x) = 11 3x + 44 + 8x = 11 <-- be careful with positive/negative signs here Now you can solve for x. You're not quite done yet but is this helping?
11x +44 =11
11x = 33
2
i wonder which the answer choice would be :(
so it's gotta be c or b!
you had a good start! 11x + 44 = 11 subtract 44 from both sides: 11x + 44 - 44 = 11 - 44 11x = -33 <-- be careful with negatives :) divide both sides by 11: (11x) / 11 = (-33)/11 x = -3
oh X = -3 so it's C
because in b y = -3 :)
Therefore it must be C. But if you want to calculate y: take x and substitute into either equation: 2x + y = -11 2(-3) + y = -11 -6 + y = -11 add 6 to both sides: -6 +6 + y = -11 + 6 y = -5 :)
thank you so much @redshift you are so nice and smart
haha thanks :)
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