Question

Divide
24b^5f^6+36b^3f^4 over 4b^3f

Answer 1

\[\frac{ 24b ^{5}f ^{6}+36b ^{3}f ^{4} }{ 4b ^{3}f }\]

Answer 2

\[\frac{ 24b ^{5}f ^{6}+36b ^{3}f ^{4} }{ 4b ^{3}f } \\ \\ \frac{ 24b ^{5}f ^{6}}{ 4b ^{3}f }+ \frac{36b ^{3}f ^{4} }{4b ^{3}f } \\ \\ \frac{ \cancel{24}^6b ^{\cancel5^2}f ^{\cancel6^5}}{ \cancel{4b ^{3}f} }+ \frac{\cancel{36}^9b ^{\cancel{3}^1}f ^{\cancel4^3} }{\cancel{4b ^{3}f }} \]

Answer 3

Which leaves you with
\[6b^2f^5+9b f^3\]

Answer 4

wait should be
\[6b^2f^5+9 f^3\]

Answer 5

What'd you do to the exponents? Add or subtract

Answer 6

b^3 and b^3 cancel out

Answer 7

if divide, subtract , if multiply, add

Answer 8

Oh okay thanks!

Answer 9

\[a^m(a^n)=a^{m+n} \\ \\ \frac{a^m}{a^n}=a^{m-n}\]

Answer 10

I'll note that thanks again