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OpenStudy (anonymous):
An object is launched upward at 64 ft/sec from a platform that is 80 feet high. What is the object's maximum height if the equation of height (h) in terms of time (t) of the object is given by h(t) = -16t2 + 64t + 80? A. 272 B. 144 C. 1232 D. 616
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OpenStudy (anonymous):
@Mertsj
OpenStudy (mertsj):
The maximum will be the vertex.
OpenStudy (mertsj):
x=-64/-32=2 Plug in 2 and find the y coordinate of the vertex. That will be the maximum.
OpenStudy (mertsj):
I got 144. What did you get?
OpenStudy (anonymous):
144:)
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OpenStudy (mertsj):
Cool
OpenStudy (anonymous):
kekek!:)
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