Question

PLEASE HELP!!! (Algebra)
please see previous question: http://openstudy.com/users/scienceqs#/updates/5148fa19e4b05e69bfab7801

I have determined that the original fraction is -33/-3.
Now, I must determine which of the following equations represents "if the numerator of the fraction is increased by 3, the fraction becomes 3/4".
options are
3n + 9 = 4d
4n + 3 = 3d
or
4n + 12 = 3d
I know that to solve this i need to use cross multiplication, but I don't know where or how.

Answer 1

thanks for coming. can u help?

Answer 2

See if numerator = n

then I have : \(\large{\frac{n+3}{\textbf{denominator}} = \frac{3}{4}}\)

let denominator = d

so \(\large{\frac{n+3}{d} = \frac{3}{4}}\)

Now cross multiply : 4(n+3) = 3d

4n + 12 = 3d

Answer 3

oh ok. that makes sense! thank you

Answer 4

Welcome To OpenStudy @ScienceQs

Also, seiga in the previous question has done a blunder. Come there.

Answer 5

ok