Question

Find four consecutive integers whose sum is 114.

Answer 1

set up an equation like this
n+n+1+n+2+n+3=114

Answer 2

If integers are consecutive, then they're in the form: x, x + 1, x + 2....

Since we got 4 consecutive integers, and we assign the value 'x' to the first time, we get :

x, x + 1, x + 2, x + 3

We know the sum of these 4 terms is 114, so:

(x) + (x + 1) + (x + 2) + (x + 3) = 114
4x + 6 = 114
4x = 108
x = 27
So now our 4 terms become:

27, 27 + 1, 27 + 2, 27 + 3, which is

27, 28, 29, 30