Question

A bacteria culture initially contains 2000 bacteria and doubles every half hour.
a) Find an expression for the number of bacteria after hours.

Answer 1

@abb0t You trolling? lol

Answer 2

OMG. LOL. i should be in bed. My final is in like 5 hrs!!!!

Answer 3

Standard equation for an exponential function base 2 (aka it doubles) \[
F(t) = C\cdot 2^{kt}
\]
"A bacteria culture initially contains 2000"
Meaning:\[
F(0) = C\cdot 2^{k(0)} = 2000
\]
"doubles every half hour"
Meaning:\[
F(1/2) = C\cdot 2^{k(1/2)} = 2\cdot 2000 = 4000
\]Two equations and two variables \(C,k\)

Answer 4

Now, if you want me to derive that exponential function, you gotta ask nicely.
It requires differential equations.

Answer 5

I mean if you want me to derive: \[
F(t) = C\cdot 2^{kt}
\]

Answer 6

show off :P

Answer 7

Yeah, but at the end of the day, I still get an inbox full of "Huh?" and no medals.

Answer 8

ok this is what i was getting but for some reason it is showing up as wrong?

Answer 9

What are you getting for \(k\) and \(C\)?

Answer 10

Is your ending formula: \[\large
F(t) = 2000\cdot 2^{2t}
\]

Answer 11

2000(2)^t/2

Answer 12

nope

Answer 13

You solved for \(k\) wrong.

Answer 14

\[
2^{k(1/2)}=2\implies k/2 = 1 \implies k=2
\]

Answer 15

@nyland1
Why is this question still open...?