Question

A bag contains 8 blue marbles, 6 red marbles, and 4 green marbles. What is the probability of selecting a blue marble, replacing it in the bag and then selecting a red marble? Compass. I need help!!

Answer 1

33.33% or 1/3 chance

Answer 2

Thanks

Answer 3

Medal me?

Answer 4

What is the total number of marbles? What fraction are blue? What fraction are red?

If you have some outcome with probability A, and another independent outcome with probability B, the probability of both events happening is A*B. Independent means the outcome of one thing does not affect the probabilities for the other thing.

In this case the events of picking the two marbles are independent, because after picking one marble, you put it back, so the contents of the bag are not changed. So you can just multiply the prob. of picking blue by the prob. of picking red.

Answer 5

Only if A and B are directly related.
@LikeLightning

Answer 6

No, multiplication is for when the events are independent (not related). Also, 1/3 is the wrong answer.

Answer 7

Chill. 6/18 is 1/3. The Probability is completely independent. The information about the first marble pulled is completely irrelevant.

Answer 8

That's not how I would interpret the problem. I think it's for the probability of drawing a blue AND a red.

Answer 9

Ah. My mistake, yes, that is probably what this is asking. And for that the answer would be; (2/9)*(3/9)