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Mathematics 7 Online
OpenStudy (anonymous):

what is 2√108

OpenStudy (merchandize):

20.784

OpenStudy (anonymous):

simplified

OpenStudy (anonymous):

bring 2 inside the square root \[2=\sqrt{4}\] the \[\sqrt{4*108}=\sqrt{432}=20.78\]

OpenStudy (anonymous):

get it?

OpenStudy (anonymous):

A: 12√3 B: 6√3 C: 144√3 D: 8√3

OpenStudy (anonymous):

your job is to look for perfect squares that are factors of 108

OpenStudy (anonymous):

I dont know how to do that.

OpenStudy (anonymous):

since it is divisible both by 4 and by 9, it is divisible by 36

OpenStudy (anonymous):

in fact, \(108=36\times 3\)

OpenStudy (anonymous):

similar if you take out of the square root \[\sqrt{432}= \sqrt{144*3}=12\sqrt{3}\]

OpenStudy (anonymous):

so \[\sqrt{108}=\sqrt{36\times 3}=\sqrt{36}\sqrt{3}=6\sqrt{3}\]

OpenStudy (anonymous):

if your question is \[2\sqrt{108}\] then the answer would be \[12\sqrt{3}\]

OpenStudy (anonymous):

Thanks !

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