Help
\[10\sqrt[4]{6} + 4\sqrt[3]{6} - 9\sqrt[3]{6} - 3\sqrt[4]{6}\]
@jim_thompson5910
What are the common terms here
\[10\sqrt[4]{6} and 3\sqrt[4]{6}\]
\[4\sqrt[3]{6} and 9\sqrt[3]{6}\]
good, so combine those pairs of like terms
for example, \(\large 10\sqrt[4]{6}\) and \(\large -3\sqrt[4]{6}\) combine to \(\large 10\sqrt[4]{6} -3\sqrt[4]{6}\) \(\large (10 -3)\sqrt[4]{6}\) \(\large 7\sqrt[4]{6}\)
how about the other pair of terms? what do they combine to?
\[-5\sqrt[3]{6}\]
so the answer is \[7\sqrt[4]{6} - 5\sqrt[3]{6}\]
@jim_thompson5910
good you got it
what about 2√6 ?
whats also an answer choice.
you want to simplify this?
Well it has what i said then my bf said 2√6 and thats also an answer choice.
oh no it's \[7\sqrt[4]{6} - 5\sqrt[3]{6}\] like you said
I have another if you dont mind @jim_thompson5910
\[\sqrt{10} (4-\sqrt{5}) + \sqrt{8} (\sqrt{5}+2)\]
\[\Large \sqrt{10} (4-\sqrt{5}) + \sqrt{8} (\sqrt{5}+2)\] \[\Large \sqrt{10} (4)-\sqrt{10} \sqrt{5} + \sqrt{8}\sqrt{5}+\sqrt{8}(2)\] \[\Large 4\sqrt{10}-\sqrt{10*5} + \sqrt{8*5}+2\sqrt{8}\] \[\Large 4\sqrt{10}-\sqrt{50} + \sqrt{40}+2\sqrt{8}\] \[\Large 4\sqrt{10}-\sqrt{25*2} + \sqrt{4*10}+2\sqrt{4*2}\] \[\Large 4\sqrt{10}-\sqrt{25}*\sqrt{2} + \sqrt{4}*\sqrt{10}+2\sqrt{4}\sqrt{2}\] \[\Large 4\sqrt{10}-5\sqrt{2} + 2\sqrt{10}+2*2\sqrt{2}\] \[\Large 4\sqrt{10}-5\sqrt{2} + 2\sqrt{10}+4\sqrt{2}\] \[\Large 6\sqrt{10}-\sqrt{2}\]
Thank youuu!
yw
\[\frac{ 2 }{ 6-\sqrt{3} } \]
Last one i Promise. lol
@jim_thompson5910
multiply top and bottom by \(\Large 6+\sqrt{3}\) and tell me what you get
12 over √ 3
no you should get this
\[\Large \frac{ 2 }{ 6-\sqrt{3} } \] \[\Large \frac{ 2(6+\sqrt{3}) }{ (6-\sqrt{3})(6+\sqrt{3}) } \] \[\Large \frac{ 2(6+\sqrt{3}) }{ 6^2 - \left(\sqrt{3}\right)^2 } \] \[\Large \frac{ 2(6+\sqrt{3}) }{ 36 - 3 } \] \[\Large \frac{ 2(6+\sqrt{3}) }{ 33 } \] \[\Large \frac{ 12+2\sqrt{3} }{ 33 } \]
Thanks!
np
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