Mathematics
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OpenStudy (anonymous):
The curve above is the graph of a sinusoidal function. It goes through the point (7,2). Find a sinusoidal function that matches the given graph
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OpenStudy (anonymous):
OpenStudy (anonymous):
@hartnn
OpenStudy (anonymous):
A sinusoidal curve is going to be in the following form: \[
f(t) = a\sin(\omega t+\phi)
\]
OpenStudy (anonymous):
Where \(a\) is the amplitude, \(\omega\) is the frequency, and \(\phi\) is the phase shift.
OpenStudy (anonymous):
i am aware of the prior information.
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OpenStudy (anonymous):
First let's find \(a\).
To find the amplitude, you want to find the difference between the top and bottom and divide by 2.
OpenStudy (anonymous):
thus far i have 2cos5.25
OpenStudy (anonymous):
\(2\cos(5.25)\)?
OpenStudy (anonymous):
That isn't a function...
OpenStudy (anonymous):
dont make me feel stupid or i will most certainly block you...
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OpenStudy (anonymous):
i realize that is not a function.
OpenStudy (anonymous):
Why don't you explain then?
OpenStudy (anonymous):
i was informing you on what i had so far. if that isn't right then you can tell me what i am doing wrong... i am here for help.
OpenStudy (anonymous):
i got 5.25 because 21/4 = 5.25
OpenStudy (anonymous):
which i assumed to be "T"
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OpenStudy (anonymous):
T as in the period?
OpenStudy (anonymous):
the 2 comes from the graph's min-max
OpenStudy (anonymous):
yes.
OpenStudy (anonymous):
"T" as in the period.
OpenStudy (anonymous):
Well, 21 gets you you a period and a half.
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OpenStudy (anonymous):
21 is one and a half wave lengths. The period is just one wave length.
OpenStudy (anonymous):
okay. i understand that now. i see where i was doing that wrong.
OpenStudy (anonymous):
i just need B
OpenStudy (anonymous):
and how to find "B" by looking at the graph
OpenStudy (anonymous):
B?
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OpenStudy (anonymous):
Is that the phase shift or something?
OpenStudy (anonymous):
Can you tell me what your equation is?
OpenStudy (anonymous):
Asin(Bx+C)
OpenStudy (anonymous):
there will be no phase shift and period is 2pi/B
OpenStudy (anonymous):
sin is interchangeable with trig functions.
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OpenStudy (anonymous):
idk the equation. that is what i am trying to figure out by just looking at the graph.
OpenStudy (anonymous):
The period is 14, that is the distance from two tops.
OpenStudy (anonymous):
That makes \(B=2\pi/14\), no?
OpenStudy (anonymous):
Because at \(0\), \(Bx=0\) and at \(14\) , \(Bx=2\pi\)
OpenStudy (anonymous):
so the equation is still not clear to me... idk how you got 14.
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OpenStudy (anonymous):
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