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Mathematics 11 Online
OpenStudy (anonymous):

The curve above is the graph of a sinusoidal function. It goes through the point (7,2). Find a sinusoidal function that matches the given graph

OpenStudy (anonymous):

OpenStudy (anonymous):

@hartnn

OpenStudy (anonymous):

A sinusoidal curve is going to be in the following form: \[ f(t) = a\sin(\omega t+\phi) \]

OpenStudy (anonymous):

Where \(a\) is the amplitude, \(\omega\) is the frequency, and \(\phi\) is the phase shift.

OpenStudy (anonymous):

i am aware of the prior information.

OpenStudy (anonymous):

First let's find \(a\). To find the amplitude, you want to find the difference between the top and bottom and divide by 2.

OpenStudy (anonymous):

thus far i have 2cos5.25

OpenStudy (anonymous):

\(2\cos(5.25)\)?

OpenStudy (anonymous):

That isn't a function...

OpenStudy (anonymous):

dont make me feel stupid or i will most certainly block you...

OpenStudy (anonymous):

i realize that is not a function.

OpenStudy (anonymous):

Why don't you explain then?

OpenStudy (anonymous):

i was informing you on what i had so far. if that isn't right then you can tell me what i am doing wrong... i am here for help.

OpenStudy (anonymous):

i got 5.25 because 21/4 = 5.25

OpenStudy (anonymous):

which i assumed to be "T"

OpenStudy (anonymous):

T as in the period?

OpenStudy (anonymous):

the 2 comes from the graph's min-max

OpenStudy (anonymous):

yes.

OpenStudy (anonymous):

"T" as in the period.

OpenStudy (anonymous):

Well, 21 gets you you a period and a half.

OpenStudy (anonymous):

21 is one and a half wave lengths. The period is just one wave length.

OpenStudy (anonymous):

okay. i understand that now. i see where i was doing that wrong.

OpenStudy (anonymous):

i just need B

OpenStudy (anonymous):

and how to find "B" by looking at the graph

OpenStudy (anonymous):

B?

OpenStudy (anonymous):

Is that the phase shift or something?

OpenStudy (anonymous):

Can you tell me what your equation is?

OpenStudy (anonymous):

Asin(Bx+C)

OpenStudy (anonymous):

there will be no phase shift and period is 2pi/B

OpenStudy (anonymous):

sin is interchangeable with trig functions.

OpenStudy (anonymous):

idk the equation. that is what i am trying to figure out by just looking at the graph.

OpenStudy (anonymous):

The period is 14, that is the distance from two tops.

OpenStudy (anonymous):

That makes \(B=2\pi/14\), no?

OpenStudy (anonymous):

Because at \(0\), \(Bx=0\) and at \(14\) , \(Bx=2\pi\)

OpenStudy (anonymous):

so the equation is still not clear to me... idk how you got 14.

OpenStudy (anonymous):

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