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OCW Scholar - Physics I: Classical Mechanics 19 Online
OpenStudy (anonymous):

In a circular motion,why does the acceleration tangential to the circle equal (2r'w + rw')?(r:radius;w:angular velocity)

OpenStudy (vincent-lyon.fr):

This is not correct, in a circular motion, the radius is fixed: r = R, so r' = 0. Tangential acceleration is simply: \(\dot v=R \dot\omega = R\alpha\) The expression you wrote is the general expression in cylindrical coordinates.

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