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Mathematics 18 Online
OpenStudy (anonymous):

See the attachment

OpenStudy (anonymous):

OpenStudy (shubhamsrg):

Do you have the answer? Is it 4/153 ?

OpenStudy (shubhamsrg):

No wait, 4/51 ?

OpenStudy (anonymous):

I don't have the answer. Probably your solution would work

OpenStudy (shubhamsrg):

I just used symmetry , a=b=c

OpenStudy (anonymous):

Sure that would work ?

OpenStudy (shubhamsrg):

not sure! :|

OpenStudy (shubhamsrg):

@RnR

OpenStudy (anonymous):

Would that be required to prove

OpenStudy (anonymous):

I dont know. :/

OpenStudy (shubhamsrg):

I was saying 0.784314 approx i.e. 4/51 , but guess the ans is 0.7082808

OpenStudy (shubhamsrg):

So my logic must be flawed ? @RnR

OpenStudy (anonymous):

MAY BE

OpenStudy (shubhamsrg):

oh wait! my answer is correct !

OpenStudy (shubhamsrg):

it says all non negative numbers.

OpenStudy (anonymous):

But, remember we will have to prove and justify each and every step.

OpenStudy (shubhamsrg):

hmm..I don't know the precise reasoning, but in most questions like these, symmetry works i.e. a=b=c. As I said, I don;t know the precise reasoning .

OpenStudy (anonymous):

Well I accept what you said about symmetry; but without reasons that wouldn't work.

OpenStudy (shubhamsrg):

@ganeshie8

OpenStudy (shubhamsrg):

@mukushla can surely guide you, but he;s not online.. hmm @experimentX also!

OpenStudy (shubhamsrg):

well you may want to wait till the experts tune in..

OpenStudy (experimentx):

this is not easy ... if it has numerical values, then Lagrange multiplies should work.

OpenStudy (anonymous):

@DarthTony How can you say that a=b=c=x 3x=9/2, x=1.5 minimum = 3/2 First prove that this statement is true.

OpenStudy (experimentx):

I think i saw similar Q on M.SE ... let me google it.

OpenStudy (anonymous):

Whats that?

OpenStudy (anonymous):

@experimentX whats M.SE

OpenStudy (experimentx):

http://math.stackexchange.com

OpenStudy (anonymous):

Ohhhhhhhhhh

OpenStudy (experimentx):

I don't think you can just solve it by AM-GM type or Cauchy Swartz type

OpenStudy (experimentx):

finding the minimum value and proving it are two different cases.

OpenStudy (experimentx):

there's similar question here http://math.stackexchange.com/questions/191431/inequality-fracaa23-fracbb23-leq-frac12?rq=1

OpenStudy (anonymous):

@dan815 I accept what you say in pts. 1 and 2 but still I don't find it sufficient to say that a=b=c will satisfy our answer. This is a difficult question and could not be solved with that ease.

OpenStudy (experimentx):

here is a similar question ... this says to look for Cauchy-Swarz

OpenStudy (anonymous):

can it be possible that a=b=0 and c=9/2.so that we get the minimum value??o is a non negative number

OpenStudy (experimentx):

looks like this Q wen't unsolved in MSE too http://math.stackexchange.com/questions/275208/the-least-value-for-fracab354-fracbc354-fracca354

OpenStudy (anonymous):

what class is this from?

OpenStudy (anonymous):

@Peter14 No class

OpenStudy (experimentx):

looks like Olympiad style Q.

OpenStudy (experimentx):

if it's just min value then try making use of Lagrange Multiplies. @DarthTony the criteria is slight different a+b+c = 9/2 .... so this might be equal your answer. If it's just finding the value without caring method, then Lagrange multiplies also work.

OpenStudy (anonymous):

@experimentX Correct said. Its an olympiad question

OpenStudy (anonymous):

\[ f(a,b,c)=\frac{a}{b^3+54}+\frac{b}{c^3+54}+\frac{c}{a^3+54}\\ g(a,b,c)=a+b+c-{9\over2}\\ f_a=\lambda g_a=\lambda\\ f_b=\lambda g_b=\lambda\\ f_c=\lambda g_c=\lambda\\ a+b+c={9\over2} \] this is the set of langrangian equations the first three derivatives must be fairly simple (each giving a relation between two variables and \(\lambda\)).

OpenStudy (anonymous):

like this: the first equ.\[{1\over b^3+54}-{3a^2c\over (a^3+4)^2}=\lambda\]

OpenStudy (anonymous):

hmm.. no global minima!! lets see.. are the partial derivatives positive?

OpenStudy (experimentx):

if a function is bounded by numerical values, then Lagrange multiplies should work.

OpenStudy (anonymous):

who is cheerful enough in the morning to continue the expansion? -> the real slim shady math guys say aye

OpenStudy (experimentx):

i wonder if it can be proved by Cauchy Schwarz. If it's just asking for the value then Lagrange multiplies as well as guessing like symmetry argument. @electrokid i give up on lagrange

OpenStudy (experimentx):

gotta go for now.

OpenStudy (anonymous):

@SheldonEinstein is this a numerical problem or an analytical one?

OpenStudy (anonymous):

Can't say as it is an olympiad one.

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