Question

What is the vertex form of y=x^2-2x-3

Answer 1

First, complete the square:

\[y=x^{2}-2x+1-4\]
and because \[(x^{2}-2x+1)=(x-1)^{2}\]

\[y=(x-1)^{2}-4\]

and that is the vertex form.

Answer 2

Okay do you know how to take that same equation into intercept form???

Answer 3

Factor \[x^{2}-2x-3=(x-3)(x+1)\]

so, \[y=(x-3)(x+1)\] is the intercept form.

Answer 4

Okay thank you so much i think i got it now.

Answer 5

No problem! :)