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OpenStudy (anonymous):

help me!

OpenStudy (anonymous):

@dramaqueen

OpenStudy (anonymous):

is this one stems or flower..?

OpenStudy (anonymous):

flower

OpenStudy (anonymous):

and this one would be stem? Buds are found on the (1 point)flowers. leaves. stems. stems and roots.

OpenStudy (anonymous):

The police department is keeping track of distracted drivers and accidents. They have found that if a driver is distracted, the driver has a 30% chance of being in an accident. If the driver is not distracted, the driver has a 2% chance of being in an accident. The probability of a driver being distracted is 10%. If needed, create a tree diagram on a separate piece of paper. Then use the diagram to answer the questions. a. What is the probability a driver will be in an accident? Explain. b. What is the probability that a driver who was in an accident was distracted? Explain.

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

Draw out a tree to get this |dw:1364249812316:dw|

jimthompson5910 (jim_thompson5910):

Now find the probability of each branch so for instance the first uppermost branch would be 0.1*0.3 = 0.03 |dw:1364249966115:dw|

jimthompson5910 (jim_thompson5910):

To find the probability of being in an accident, add up the accident probabilities to get 0.03+0.018 = 0.048

jimthompson5910 (jim_thompson5910):

What is the probability that a driver who was in an accident was distracted? P(Distracted|Accident) = P(Distracted and Accident)/P(Accident) P(Distracted|Accident) = ???

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