Question

Lost again

Answer 1

\[\int\limits_{}^{}\frac{ cosx }{ 3sinx+9 }dx\]

Answer 2

so u= sinx
du/dx= cosx

Answer 3

du=cosxdx

Answer 4

You want to get that whole denominator.

Answer 5

\[
u=3\sin x+9,\;du=3\cos x\;dx
\]

Answer 6

so I would end up with ln(u)/3?

Answer 7

yup

Answer 8

so now this next one has the dx inside the problem

Answer 9

But that's in terms of \(u\).

Answer 10

yeah I got once I used the right u, just had to put the 3sinx+9 back in for u