3x-y=5 7x-2y=13 what is the solution?
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do i multiply 3x5?
It depends. Is this a system of equations or two separate equations?
system of equations
3x-y=5 7x-2y=13 Start off by solving the first equation for y. Can you do that?
iam not very good at math, iam good at the basics like multiply,divide,adding,subtracting
Alright. So solve an equation you want to do the oppsite. 3x - y = 5 So, we subtract 3x -y = -3x + 5 Now, y cannot be negative so we divide y = 3x - 5 Got it? Now, we know y = 3x - 5, so plug that into the equation below it. 7x-2(3x - 5) =13 <-- now solve for x.
1. chose any of the two equations that your are comfortable with in finding "x" 2. in this situation, i chose 3x-y=5 3x - y = 5 3x = 5 +y (transpose y to the other side) x = 5/3 + y/3 (divide both sides by 3) 3. now, substitute the value of "x" to the second equation 7x - 2y = 13 7(5/3 + y/3) - 2y = 13 4. multiply the one inside in the parenthesis by 7: 35/3 + 7y/3 - 2y = 13 7y/3 - 2y = 13 - 35/3 (transpose 35/3 to the other side) 5. since the common denominator is 3, multiply both sides by 3 now it will become; 7y -6y = 39 -35 y = 4 6. substitute to either of the two equations: i chose 3x - y = 5 3x - (4) = 5 (substitute "y" to "4") 3x = 5 +4 (transpose 4 to the other side) 3x = 9 x = 3 (divide both sides by 3) the answer is x=3 and y=4 how to know if your solution is correct? substitute either of the two equations the values of "x" and "y" i chose 7x - 2y = 13 7(3) - 2(4) = 13 21 - 8 = 13 13 = 13 therefore, the solution is correct....
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