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The implied domain of y = arcsin[cos(-2x)] is: A - [-pi/2 , 0] B - [0 , pi/2] C - [/pi , pi] D - [-pi/4 , pi/4] E [-2pi , 2pi]
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\[ \sin(y)=\cos(-2x) \]
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\[ \cos(\pi/2-y) = \cos(-2x)\implies \pi/2-y = -2x \]
I'm just messing around.
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Okay because I am really confused haha
Okay so basically we want to know the minimum angles to get \[ \cos(-2x)=1,\;\cos(-2x)=-1 \]
0 is one of them.
Honestly, this question is really weird, isn't it?
Yeah haha
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I don't see any real restriction on the domain.
Oh well, don't worry, thanks anyway :)
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