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Mathematics 14 Online
OpenStudy (anonymous):

A student analyses his work every sunday. The probability of the student being upto date in a given week if he's upto date in the previous week is 0.8. The probability of a student being upto date if he's not upto date in the previous week is 0.6. Given he's upto date on the first sunday, what is the probability that he will be upto date after 3 weeks?

OpenStudy (anonymous):

@shubhamsrg

OpenStudy (anonymous):

@DLS

OpenStudy (notamathgenius):

.8, .6, .4, .2, 0

OpenStudy (anonymous):

What?

OpenStudy (anonymous):

And i'm not writing anything. OS is being crazy.

OpenStudy (anonymous):

What do you mean by Os is being crazy @RnR ?

OpenStudy (anonymous):

there are four possibilities case 1: week 1 uptodate , week2 uptodate then find P(uptodate in third week) case 2: week1 not uptodate, week2 not uptodate , then find P(uptodate in third week) case 3:week1 not uptodate, week2 uptodate , then find P(uptodate in third week) case 4:week1 uptodate, week2 not uptodate , then find P(uptodate in third week) as we already no that first sunday was uptodate and further The probability of the student being not upto date in a given week if he's upto date in the previous week is 1-0.8 = 0.2. The probability of a student being not upto date if he's not upto date in the previous week is 1-0.6 = 0.4.

OpenStudy (dls):

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