Question

\[\sum_{k=2}^{3} (k ^{2}-2k)\]
so confused

Answer 1

what is the confusion about?

Answer 2

the value at k=2, added to the value at k=3 .... seems simple enough

Answer 3

I can't seem to find the sum of the series

Answer 4

I have done it twice and still not getting the right answer

Answer 5

show me your work then

Answer 6

there are a few ways to approach this ... so knowing what way you tried will help determine your errors

Answer 7

2^2-2(2)= 0
3^2-2(3)= 3
4^2-2(4)= 8
the sum would be 11 if 8+3 is added we get 11

Answer 8

well, your adding is good, but im curious why you want to k=4? your index says k = 2 to 3

Answer 9

oh crap I went to far didn't I

Answer 10

over and beyond :)

Answer 11

my bad

Answer 12

so the answer would 3

Answer 13

yes, with what you have posted i would say 3 is correct

Answer 14

thank you

Answer 15

youre welcome, good luck :)