For y=x^2-36, can someone tell me what the equation would look like sketched out on a graph? I am horrible with graphing and what the vertex would be?
Can you tell that it is a parabola shifted down 36 units?
The best thing to do is to make a table of \(x\) and \(y\) values and plot each point.
while drawing a graph,the points you get most easily are the ones for which the value of the other variable becomes zero.that is,values of x for which y is zero and vice versa.plot these points on the graph
since this is a quadratic equation,its graph will be a parabola.do you know how a parabola looks like?
I do know what one looks like
for y=0,x has two values 6,-6.and for x=0,y=-36|dw:1364158667348:dw|
if you know how a parabola looks like,i am sure you can do the rest yourself
Yep! Can you tell me what the vertex is though?
0,-36
are you still having some problem?
Yes sorry my computer froze.
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