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Mathematics 14 Online
OpenStudy (anonymous):

For y=x^2-36, can someone tell me what the equation would look like sketched out on a graph? I am horrible with graphing and what the vertex would be?

OpenStudy (anonymous):

Can you tell that it is a parabola shifted down 36 units?

OpenStudy (anonymous):

The best thing to do is to make a table of \(x\) and \(y\) values and plot each point.

OpenStudy (anonymous):

while drawing a graph,the points you get most easily are the ones for which the value of the other variable becomes zero.that is,values of x for which y is zero and vice versa.plot these points on the graph

OpenStudy (anonymous):

since this is a quadratic equation,its graph will be a parabola.do you know how a parabola looks like?

OpenStudy (anonymous):

I do know what one looks like

OpenStudy (anonymous):

for y=0,x has two values 6,-6.and for x=0,y=-36|dw:1364158667348:dw|

OpenStudy (anonymous):

if you know how a parabola looks like,i am sure you can do the rest yourself

OpenStudy (anonymous):

Yep! Can you tell me what the vertex is though?

OpenStudy (anonymous):

0,-36

OpenStudy (anonymous):

are you still having some problem?

OpenStudy (anonymous):

Yes sorry my computer froze.

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