Question

What are the excluded values for this rational expression 6x^3y^2/2xy

Answer 1

Any value of a variable that causes the denominator to be 0. What might that be?

Answer 2

I'm not sure how I would do that

Answer 3

What is the denominator?

Answer 4

2xy

Answer 5

If x = 1, and y = 2 will the denominator be 0?

Answer 6

Yes?

Answer 7

So 2 (1)(2)=0?????

Answer 8

no, I'm sorry im not good at this

Answer 9

The denominator is 2xy as you said. That means 2 times x times y.

Answer 10

That product cannot be 0. The only way a product can be 0 is if one of the factors is 0

Answer 11

For sure, 2 will never be 0. So the denominator, 2xy, will be 0 if x is 0. Do you agree with that?

Answer 12

Yes

Answer 13

Also the denominator, 2xy will be 0 if y is 0. Do you agree with that?

Answer 14

Yes

Answer 15

But remember, the denominator cannot be 0 because dividing by 0 is meaningless. So we exclude x=0 and y = 0 from the list of numbers that x and y can be. so those are the excluded values that the problem asks for.

Answer 16

Okay thank you very much

Answer 17

yw